a phone company offers two monthly charge, in Plan a, the customer pays a monthly fee of $40.10 and then an additional 4 cents per minute of use. In plan b, the Customer pays a monthly fee of $35 and then an additional 7 cents per minute of use. for what amounts of monthly phone use will plan a cost no more than Plan B

Answer:x > 1.7 minutes The monthly telephone usage amounts so that plan A is not greater than plan B are all greater than 1.7 minutes. Step-by-step explanation:The two plans must be defined by the equation of the line y = mx + b, where y = plan m = slope or payment of additional cents per minute x = time expressed in minutes For Plan A, we have y = 4x + 40.10 (Equation A) While plan B is defined as y = 7x + 35 (Equation B) Plan A must be less than Plan B, 4x + 40.10 < 7x + 35 We put the “x” on the left side and the independent terms on the right side, 4x - 7x < 35 - 40.10 We add algebraically, -3x < -5.10 We multiply the equation by -1 to eliminate the two “minus” signs, changing the inequality sign, 3x > 5.10 We isolate x, x > 5.10 / 3 We solve, calculating the value of x, x > 1.7 minutes The monthly telephone usage amounts so that plan A is not greater than plan B are all greater than 1.7 minutes.