Tom throws a Frisbee into the air from a height of 4 feet withan initial vertical velocity of 64 feet per second. Use the verticalmotion model, h = -16t2 + vt +s, where v is the initial velocity infeet/second and s is the height in feet, to calculate themaximum height of the frisbee. Round your answer to thenearest tenth if necessary.Maximum height: — feetEnter the answerCheck it
Accepted Solution
A:
Answer:68 feetStep-by-step explanation:Vertical motion model:h = -16t² + vt + sGiven v = 64 and s = 4:h = -16t² + 64t + 4This is a parabola. The maximum of a parabola is at the vertex.For y = ax² + bx + c, the vertex is at x = -b/(2a).Therefore, the time to reach the maximum height is:t = -64 / (2 × -16)t = 2And the maximum height is:h = -16(2)² + 64(2) + 4h = 68So the Frisbee reaches a maximum height of 68 feet.